Silly Questions....

[me_akron]

Please ... no offense...

How do you say "Mum's the word" to a mute? Or should you?

 

[babydoll2u]

No, they die of 'natural' causes.

Are you having a good evening?

LOL...

hiya Kik... good to see you hun..
hope you're having a good evening

 

[babydoll2u]

How many times have you done it... since you were never going to do it again?

lol... depends on what "it" is?

 

[me_akron]

Why do you good ones in the East always tell us Westerns that the good ones are far away? When we know it?

 

[babydoll2u]

Why do you good ones in the East always tell us Westerns that the good ones are far away? When we know it?

LOL... I love your sig line!

 

[babydoll2u]

no offense intended


Which bathrooms do transsexuals use?

 

[babydoll2u]

In keeping with the Nascar spirit!

Does Jeff Gordon get nervous when someone passes him on the freeway?

 

[Quoll]

Hopefully give yourself a big hug from me. ((((((((((quoll))))))))))

Well....... I was stuck for ideas, but I really like that one

and right back at you.((((((((((KIKI))))))))))



How fast is too fast.?

 

[babydoll2u]

how slow is too slow?

 

[Quoll]

How high is too high?

 

[me_akron]

How come

when a gal passes and you check out her stern with a stern look... your GF gives you a stern look?

 

[babydoll2u]

how low is too low?

 

[Quoll]

how low is too low?

A good*SLAAAP* across the face! youve gone too low.

 

[me_akron]

Not a riddle but could be

Wouldn't you think everything was great when she went North and he went South?

Especially on Lit?

 

[pleasteasme]

Why does toilet water swirl clockwise in America and counterclockwise in Australia?

 

[Quoll]

Why does toilet water swirl clockwise in America and counterclockwise in Australia?

Below is an attempt at analysis to try to answer the two and fro-ing about Coriolis. It is right that the Coriolis effect is always there, however it is definitely negligible in a bathtub sized body of water draining at a reasonable rate:

The governing equations for a homogeneous, incompressible inviscid fluid are the Euler equations. When you add the vertical component of the Coriolis force, you get:

du/dt + u(du/dx) + v(du/dy) - fv = -g(dh/dx)

dv/dt + u(dv/dx) + v(dv/dy) + fu = -g(dh/dy)

dh/dt + u(dh/dx) + v(dh/dy) + h(du/dx) + h(dv/dy) = 0

Where u and v are the two horizontal components of the velocity and h is the thickness of the fluid. 'f' is 2*Omega*sin(Phi), with Omega being 2 Pi/(1 day) and Phi being the latitude.

When you assume that the velocity scales like U, and the horizontal length scale like L, then the ratio of the nonlinear terms to the Coriolis terms is

U / f L

For a bathtub, we have U=O(0.1 m/s), L=O(0.1 m), and at mid-latitudes we have f=O(.0001/s). So the ratio is O(10,000), meaning that the nonlinear terms are 4 orders of magnitude bigger than the Coriolis terms. So for a quasi-steady swirling flow, the dominant balance is going to be the nonlinear (centrifugal) terms against the pressure gradient. The Coriolis force will be utterly negligible....


An alternate scaling contrasts the size of the Coriolis term with the size of the acceleration term. The ratio of du/dt over fv is (1/(Tf)), where T is the time scale of the flow. In order for the Coriolis terms to be O(1), the time scale would have to be of the order of (1/f) or 10000 seconds (3 hours). Most of us don't put up with bathtub drains that slow!


There, I hope that`s cleared that up

 

[pleasteasme]

Below is an attempt at analysis to try to answer the two and fro-ing about Coriolis. It is right that the Coriolis effect is always there, however it is definitely negligible in a bathtub sized body of water draining at a reasonable rate:

The governing equations for a homogeneous, incompressible inviscid fluid are the Euler equations. When you add the vertical component of the Coriolis force, you get:

du/dt + u(du/dx) + v(du/dy) - fv = -g(dh/dx)

dv/dt + u(dv/dx) + v(dv/dy) + fu = -g(dh/dy)

dh/dt + u(dh/dx) + v(dh/dy) + h(du/dx) + h(dv/dy) = 0

Where u and v are the two horizontal components of the velocity and h is the thickness of the fluid. 'f' is 2*Omega*sin(Phi), with Omega being 2 Pi/(1 day) and Phi being the latitude.

When you assume that the velocity scales like U, and the horizontal length scale like L, then the ratio of the nonlinear terms to the Coriolis terms is

U / f L

For a bathtub, we have U=O(0.1 m/s), L=O(0.1 m), and at mid-latitudes we have f=O(.0001/s). So the ratio is O(10,000), meaning that the nonlinear terms are 4 orders of magnitude bigger than the Coriolis terms. So for a quasi-steady swirling flow, the dominant balance is going to be the nonlinear (centrifugal) terms against the pressure gradient. The Coriolis force will be utterly negligible....


An alternate scaling contrasts the size of the Coriolis term with the size of the acceleration term. The ratio of du/dt over fv is (1/(Tf)), where T is the time scale of the flow. In order for the Coriolis terms to be O(1), the time scale would have to be of the order of (1/f) or 10000 seconds (3 hours). Most of us don't put up with bathtub drains that slow!


There, I hope that`s cleared that up

Wow....yup, clear

If my tub drained that slow, I would think there was some serious blockage and bust out with the draino.....

 

[babydoll2u]

A good*SLAAAP* across the face! youve gone too low.

OOOOOUUUUUUUUCHHH!

 

[babydoll2u]

Re: Not a riddle but could be

Wouldn't you think everything was great when she went North and he went South?

Especially on Lit?

LOL

 

[babydoll2u]

Below is an attempt at analysis to try to answer the two and fro-ing about Coriolis. It is right that the Coriolis effect is always there, however it is definitely negligible in a bathtub sized body of water draining at a reasonable rate:

The governing equations for a homogeneous, incompressible inviscid fluid are the Euler equations. When you add the vertical component of the Coriolis force, you get:

du/dt + u(du/dx) + v(du/dy) - fv = -g(dh/dx)

dv/dt + u(dv/dx) + v(dv/dy) + fu = -g(dh/dy)

dh/dt + u(dh/dx) + v(dh/dy) + h(du/dx) + h(dv/dy) = 0

Where u and v are the two horizontal components of the velocity and h is the thickness of the fluid. 'f' is 2*Omega*sin(Phi), with Omega being 2 Pi/(1 day) and Phi being the latitude.

When you assume that the velocity scales like U, and the horizontal length scale like L, then the ratio of the nonlinear terms to the Coriolis terms is

U / f L

For a bathtub, we have U=O(0.1 m/s), L=O(0.1 m), and at mid-latitudes we have f=O(.0001/s). So the ratio is O(10,000), meaning that the nonlinear terms are 4 orders of magnitude bigger than the Coriolis terms. So for a quasi-steady swirling flow, the dominant balance is going to be the nonlinear (centrifugal) terms against the pressure gradient. The Coriolis force will be utterly negligible....


An alternate scaling contrasts the size of the Coriolis term with the size of the acceleration term. The ratio of du/dt over fv is (1/(Tf)), where T is the time scale of the flow. In order for the Coriolis terms to be O(1), the time scale would have to be of the order of (1/f) or 10000 seconds (3 hours). Most of us don't put up with bathtub drains that slow!


There, I hope that`s cleared that up

Q... you just ain't right baby

 

[onemoreguy1]

And in extension...

Below is an attempt at analysis to try to answer the two and fro-ing about Coriolis. It is right that the Coriolis effect is always there, however it is definitely negligible in a bathtub sized body of water draining at a reasonable rate:

The governing equations for a homogeneous, incompressible inviscid fluid are the Euler equations. When you add the vertical component of the Coriolis force, you get:

du/dt + u(du/dx) + v(du/dy) - fv = -g(dh/dx)

dv/dt + u(dv/dx) + v(dv/dy) + fu = -g(dh/dy)

dh/dt + u(dh/dx) + v(dh/dy) + h(du/dx) + h(dv/dy) = 0

Where u and v are the two horizontal components of the velocity and h is the thickness of the fluid. 'f' is 2*Omega*sin(Phi), with Omega being 2 Pi/(1 day) and Phi being the latitude.

When you assume that the velocity scales like U, and the horizontal length scale like L, then the ratio of the nonlinear terms to the Coriolis terms is

U / f L

For a bathtub, we have U=O(0.1 m/s), L=O(0.1 m), and at mid-latitudes we have f=O(.0001/s). So the ratio is O(10,000), meaning that the nonlinear terms are 4 orders of magnitude bigger than the Coriolis terms. So for a quasi-steady swirling flow, the dominant balance is going to be the nonlinear (centrifugal) terms against the pressure gradient. The Coriolis force will be utterly negligible....


An alternate scaling contrasts the size of the Coriolis term with the size of the acceleration term. The ratio of du/dt over fv is (1/(Tf)), where T is the time scale of the flow. In order for the Coriolis terms to be O(1), the time scale would have to be of the order of (1/f) or 10000 seconds (3 hours). Most of us don't put up with bathtub drains that slow!


There, I hope that`s cleared that up

And...
I suppose Schuler's Period accounts for the 'slosh'... although 84 minutes does seem a long time to wait.

 

[Quoll]

Re: And in extension...

And...
I suppose Schuler's Period accounts for the 'slosh'... although 84 minutes does seem a long time to wait.

I really don`t think Mrs Schuler would appreciate us discussing her period, especially if she.... er...um....sloshes for 84 mins......eeewwwww.

Apologies to Mrs Schuler.

 

[babydoll2u]

Re: Re: And in extension...

I really don`t think Mrs Schuler would appreciate us discussing her period, especially if she.... er...um....sloshes for 84 mins......eeewwwww.

Apologies to Mrs Schuler.

LOL!

 

[onemoreguy1]

Re: Re: And in extension...

I really don`t think Mrs Schuler would appreciate us discussing her period, especially if she.... er...um....sloshes for 84 mins......eeewwwww.

Apologies to Mrs Schuler.

hmmm... now here's a silly question...

After that dissertation on Coriolis Effect and the close tie to Mr. Schuler... was that humorous?

PDEQ's and all?

Well helloooooo Ms. Schuler! (and she really does prefer the Ms prefix to Mrs.)

 

[babydoll2u]

Re: Re: Re: And in extension...

hmmm... now here's a silly question...

After that dissertation on Coriolis Effect and the close tie to Mr. Schuler... was that humorous?

PDEQ's and all?

Well helloooooo Ms. Schuler! (and she really does prefer the Ms prefix to Mrs.)