Math lovers?

[channel50]

I was wondering if there were any female math lovers on this site.

Considering thats all i do and it consumes me

My AIM is Deckofmagiccards
(don't ask was into magic tricks at the time)

 

[Noor]

I was wondering if there were any female math lovers on this site.

Considering thats all i do and it consumes me

My AIM is Deckofmagiccards
(don't ask was into magic tricks at the time)

I am pretty fond of base 5

 

[channel50]

True, base 2 and 3 are too popular to choose. But integer mods require groups, and i am but a singularity....

Wow i just math insulted myself hahaha =D

 

[Noor]

True, base 2 and 3 are too popular to choose. But integer mods require groups, and i am but a singularity....

Wow i just math insulted myself hahaha =D

LOL! pretty good.

Most bright guys go through a magic phase during their teens, some never get beyond it.

 

[MollyDolly]

hehe I am no good with math, but I read a great math pick up line the other day: I wish I was sine squared and you were cosine squared so together we could be one hehe Sorry, I hated math in highschool- only really clued in in college...

 

[uacabbage]

I know my calculus, you plus me equals us.

Quick, someone name that tv show

 

[BoomerP]

I like to play minesweeper at work when I'm bored. That's math no?

 

[channel50]

Yes i know many groups that state that derivative joke, its still funny

There is one for the integral

"I used you for (integral) of e^x and it was wrong but it felt so right"

Write it out

 

[Amanda_Mc]

Mathematical Induction Proof

Let's get serious.

I'm working on the following:

Consider a rectangle and n straight line segments, each of which begins on one side of the rectangle and ends on another side. Prove, by mathematical induction, that the resulting map can be colored using exactly two colors, so that bordering regions are of different colors.

The proof has a really neat twist to it.

Mandy

 

[Missdemeanour]

See my sig!

 

[channel50]

This sounds like a combinatorics proof

my combinatorics is rusty but i think you can just denote each segment (or vertex, however you want to look at it) as 1 or 0 and go from there.

 

[Amanda_Mc]

Think reflections rather than graph theory.

 

[channel50]

Keep it going